this book goes to my mom and my dad saying one day ill do
good in life and be a writer haaa sike wats up people cool
boook im gana make yeaahhh!!!! ;)

mrs.gamble,3rd block,one of the coolest teachers

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graphing horizontal and vertical linesTo identify the location of this point, start at the origin (0, 0)
and move right along the x-axis until you are under the point.
Look at the label on the x-axis.
The 4 indicates that, from the origin, you have traveled four units to
the right along the x-axis. This is the x-coordinate, the first number in
the ordered pair.

From 4 on the x-axis move up to the point and notice the number with which
it aligns on the y-axis. The 3 indicates that, after leaving the x-axis,
you traveled 3 units up in the vertical direction, the direction of the y-axis.
This number is the y-coordinate, the second number in the ordered pair.
With an x-coordinate of 4 and a y-coordinate of 3, you have the ordered pair (4, 3).

EX:y=5 and x=3

graphing y=mx
1.Write the point-slope form of an equation of the line that passes
through the given point and has the given slope:
2.Write the standard form of an equation of the line that passes through
the given point and has the given slope
3.Write the point-slope form of an equation of the line that passes
through each pair of points

EXy=mx+b
y=2x+3
2/1 slope
(0,3) intersept

y=2xt4

graphing ax+by=c3x-2y%2B8=0
Step 1. x-intercept occurs when y=0 and y-intercept occurs when x=0.
Step 2. So at x=0 then
3%2A0-2y%2B8=0
8=2y
y=4 So y-intercept is 4 at point (0,4)
Step 3. At y=0 then
3x-2%2A0%2B8=0 3x=-8
x=-8%2F3 So x-intercept is -8/3 at point (-8/3,0)
Step 4. Here's the graph and note the x-intercept and y-intercept points on the graph.

EXEquation 3+x+%2B+-2+y+=+-8 describes a sloping line. For any
equation ax+by+c = 0, slope is -a%2Fb+=+-3%2F-2.

X intercept is found by setting y to 0: ax+by=c becomes ax=c.
that means that x = c/a. -8/3 = -2.66666666666667.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b.
Y intercept is -8/-2 = 4.
Slope is -3/-2 = 1.5.
Equation in slope-intercept form: y=1.5*x+4.

graphing inequalities part 1en But when you did those one-variable inequalities (like x < 3),
you didn't bother with "test points"; you just shaded one side or the other.
Ignore the "test point" stuff,
and look at the original inequality: y < 2x + 3. this is where I need to shade one side of the line or the other. Now think about it:
If I need y LESS THAN the line, do I want ABOVE the line, or BELOW? Naturally,
I want below the line. So I shade it in

EXy<4x-5L y=4x-5, in slope-intercept form y=mx%2Bb, slope is m=4 and the y-intercept is b=-5
Since b=-5,

exy>1/2

graphing inequalities part 11To graph a horizontal line that goes through a given point,
first plot that point. Then draw a straight line left and right
that goes through the point To graph a vertical line that goes through a given point, first plot that point.
Then draw a straight line up and down that goes through the point,